r(r-3)=r^2+12

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Solution for r(r-3)=r^2+12 equation: 


Simplifying
r(r + -3) = r2 + 12

Reorder the terms:
r(-3 + r) = r2 + 12
(-3 * r + r * r) = r2 + 12
(-3r + r2) = r2 + 12

Reorder the terms:
-3r + r2 = 12 + r2

Add '-1r2' to each side of the equation.
-3r + r2 + -1r2 = 12 + r2 + -1r2

Combine like terms: r2 + -1r2 = 0
-3r + 0 = 12 + r2 + -1r2
-3r = 12 + r2 + -1r2

Combine like terms: r2 + -1r2 = 0
-3r = 12 + 0
-3r = 12

Solving
-3r = 12

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Divide each side by '-3'.
r = -4

Simplifying
r = -4

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